12x^2+5x-7=0

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Solution for 12x^2+5x-7=0 equation:


Simplifying
12x2 + 5x + -7 = 0

Reorder the terms:
-7 + 5x + 12x2 = 0

Solving
-7 + 5x + 12x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -1x)(7 + -12x) = 0

Subproblem 1

Set the factor '(-1 + -1x)' equal to zero and attempt to solve: Simplifying -1 + -1x = 0 Solving -1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1x = 0 + 1 -1x = 0 + 1 Combine like terms: 0 + 1 = 1 -1x = 1 Divide each side by '-1'. x = -1 Simplifying x = -1

Subproblem 2

Set the factor '(7 + -12x)' equal to zero and attempt to solve: Simplifying 7 + -12x = 0 Solving 7 + -12x = 0 Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -12x = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -12x = 0 + -7 -12x = 0 + -7 Combine like terms: 0 + -7 = -7 -12x = -7 Divide each side by '-12'. x = 0.5833333333 Simplifying x = 0.5833333333

Solution

x = {-1, 0.5833333333}

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